(8x)^2=18(18+14)

Solution for (8x)^2=18(18+14) equation:

(8x)^2=18(18+14)

We move all terms to the left:

(8x)^2-(18(18+14))=0

We add all the numbers together, and all the variables

8x^2-(1832)=0

We add all the numbers together, and all the variables

8x^2-1832=0

a = 8; b = 0; c = -1832;
Δ = b2-4ac
Δ = 02-4·8·(-1832)
Δ = 58624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{58624}=\sqrt{256*229}=\sqrt{256}*\sqrt{229}=16\sqrt{229}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{229}}{2*8}=\frac{0-16\sqrt{229}}{16}
=-\frac{16\sqrt{229}}{16}
=-\sqrt{229}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{229}}{2*8}=\frac{0+16\sqrt{229}}{16}
=\frac{16\sqrt{229}}{16}
=\sqrt{229}
$